#033 Mar 21, 2026

33. std::mem::take

Ever tried to move a value out of a &mut reference? The borrow checker won’t let you — but std::mem::take will. It swaps the value out and leaves Default::default() in its place.

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use std::mem;

let mut name = String::from("Ferris");
let taken = mem::take(&mut name);

assert_eq!(taken, "Ferris");
assert_eq!(name, ""); // left with String::default()

This is especially useful when working with enum state machines where you need to consume the current state:

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use std::mem;

enum State {
    Running(String),
    Stopped,
}

impl Default for State {
    fn default() -> Self { State::Stopped }
}

fn reset(state: &mut State) -> Option<String> {
    match mem::take(state) {
        State::Running(data) => Some(data),
        State::Stopped => None,
    }
}

Without mem::take, you’d need .clone() or unsafe gymnastics to get the value out. See also mem::replace for when you want to specify what to leave behind instead of using Default.

This post is licensed under CC BY 4.0 by the author.